The mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.
What is the mass of carbon required to produce iron from iron (iii) oxide?
The mass of carbon required to produce iron from iron (iii) oxide is determined from the equation of the reaction.
From the given equation of reaction, 3 moles of carbon produces 4 moles of iron.
- Moles of a substance = mass/molar mass
Molar mass of iron = 56.0 g
molar mass of carbon = 12.0 g
Moles of iron in 5.67 g of iron = 5.67/56 = 0.1 moles
Moles of carbon required = 3/4 × 0.1 = 0.75 moles
Mass of carbon = 0.75 × 12 = 9.0 g
Therefore, the mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.
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