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QUESTION 2 (Start on a new page.) A rope is used to apply a force of 240 N to a 50 kg crate to pull it down a rough inclinod surface at a CONSTANT VELOCITY. The inclinod surface makoc an anglo of 12° with the horizontal as shown in the diagram below. 50 kg 240 N 12° (2) 2.1 State Newton's Second Law of Motion in words. (4) 2.2 Draw a labelled, free-body diagram of all the forces acting on the crate. (2) 2.3 Define the term kinetic frictional force. 2.4 Calculate the: 2.4.1 Magnitude of the kinetic frictional force between the crate and the rough inclined surface (4) 2.4.2 Value of the coefficient of kinetic frictional force (uk) between the crate and the rough inclined surface (4) [16]​

Respuesta :

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(a) The kinetic frictional force between the crate and the rough inclined surface is 240 N.

(b) The coefficient of kinetic frictional force (uk) between the crate and the rough inclined surface is 0.5.

Newton's second law of motion

Newton's second law of motion states that the force applied to an object is directly proportional to the acceleration of the object.

F = ma

Kinetic frictional force

Kinetic frictional force is the force that tends to oppose the object in motion.

F - Ff = ma

at constant velocity, a = 0

F - Ff = 0

Ff = F

Ff = 240 N

Coefficient of kinetic friction

Ff = μmg x cosθ

240 = μ(50)(9.8) x cos(12)

240 = 479.29μ

μ = 240/479.29

μ = 0.5

Learn more about coefficient of kinetic friction here: https://brainly.com/question/20241845

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