Respuesta :
The pH of 9.643 of 50 ml of 0.1000 M methylamine solution after the following volume of 0.1000 M HNO₃; where added 0
What is pH Value ?
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
- n(CH₃NH₂) = Cm x V = 0.1 x 0.05 = 0.005mol
- n(HNO₃) = CM x V = 0.1 x 0 = 0 mol
CH₃NH₂ + H₂O = CH₃NH₃⁺ + OH⁻
1mol CH₃NH₂ => 1 mol OH⁻
0.1 M => X = 0.1 M OH⁻
Methylamine, CH₃NH₂, is a weak base that reacts with water according to the above equation.
- For this reaction at equilibrium,
Kb = 4.4 x 10⁻⁴
Cm (OH⁻) = 0.1 x 4.4 x 10⁻⁴= 4.4 x10⁻⁵ M
pOH = -log [OH⁻] = - log (4.4 x 10⁻⁵) = 4.357
Using ;
pH + pOH = 14
we find the pH value:
pH = 14 - pOH = 14 - 4.357 = 9.643
In the similar way, It can be done for 25,3,50,55 and 60
Learn more about pH here ;
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