Answer:
[tex]\textsf {See below :-}[/tex]
Step-by-step explanation:
[tex]\textsf {Relation to keep in mind :}\\[/tex]
[tex]\implies \mathsf {Area = length^{2}}[/tex]
[tex]\textsf {Question 34}[/tex]
[tex]\implies \mathsf {\frac{135}{15} = (\frac{15}{XY})^{2} }[/tex]
[tex]\implies \mathsf {XY^{2} = \frac{15^{3}}{135}}}[/tex]
[tex]\implies \mathsf {XY = 5}[/tex]
[tex]\textsf {Question 35}[/tex]
[tex]\implies \mathsf {\frac{378}{168} = (\frac{XY}{8})^{2} }[/tex]
[tex]\implies \mathsf {XY= \sqrt{\frac{378 \times 64}{168}}}[/tex]
[tex]\implies \mathsf {XY = \sqrt{144}}[/tex]
[tex]\implies \mathsf {XY = 12}[/tex]
