contestada

The following data was collected when a reaction was performed experimentally in the laboratory.
Reaction Data
Reactants
Products
AI(NO3)3 NaCl NaNO3 AICI3
Starting Amount in Reaction 4 moles 9 moles ?
?
Determine the maximum amount of AlCl3 that was produced during the experiment. Explain how you determined this amount.

The following data was collected when a reaction was performed experimentally in the laboratory Reaction Data Reactants Products AINO33 NaCl NaNO3 AICI3 Startin class=

Respuesta :

shristiparmar1221

The maximum amount of [tex]AlCl_3[/tex] produced during the experiment can be find out by knowing the Limiting Reagent.

Here, The maximum amount of [tex]AlCl_3[/tex] produced during the experiment is  400 grams

What is Limiting reagent ?

The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is stopped.

Now, According to the question,

Given ;

Number of moles of [tex]Al(NO_3)_3[/tex] - 4 moles

Number of moles of NaCl - 9 moles

To Find - Maximum amount of [tex]AlCl_3[/tex] produced during the reaction.

Solution ;

complete reaction ;

[tex]Al(NO_3)_3[/tex]  + 3NaCl -->   [tex]3NaNO_3[/tex] + [tex]AlCl_3[/tex]

To find the maximum amount of [tex]AlCl_3[/tex] produced during the reaction,

we need to find the limiting reagent.

Mole ratio [tex]Al(NO_3)_3[/tex]  = 4/1 = 4

Mole ratio NaCl = 9/3 = 3

Thus, NaCl is the limiting reagent in the reaction.

Now, 3 moles of NaCl produces 1 mole of   [tex]Al(NO_3)_3[/tex]

9 moles of NaCl will produce = 1/3 x 9 = 3 moles.

Weight of   [tex]Al(NO_3)_3[/tex] = 3 x 133.34 = 400 grams

Thus, 400 grams of   [tex]Al(NO_3)_3[/tex]  is the maximum amount of   [tex]Al(NO_3)_3[/tex] produced during the experiment.

Learn more about Limiting Reagent Here ;

https://brainly.com/question/20070272

#SPJ1

Otras preguntas