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a 40 kg rock lies at a bottom of a lake. The volume of water it displaces is 800cm³. Calculate the minimum force required to lift the rock from the bottom of the lake.​

Respuesta :

Answer:

384.6 N

Explanation:

The rock is buoyed up by a force of the water it displaces

800 cm^3   of water is   800 gm

the force required to lift the rock will then be

 40 kg - 800 gm = 39.2 kg

F = ma  = 39.2 * 9.81 = 384.6 N

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