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There are n counters in a bag.
3 of the counters are red.
Two counters are taken from the bag.
Find, in terms of n, the probability that both counters are red.

Respuesta :

konrad509

[tex]\displaystyle |\Omega|=\binom{n}{2}=\dfrac{n!}{2!(n-2)!}=\dfrac{n(n-1)}{2}\\|A|=\binom{3}{2}=3\\\\P(A)=\dfrac{3}{\dfrac{n(n-1)}{2}}=\dfrac{6}{n(n-1)}[/tex]

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