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Express your answer as a complete ionic equation including phases. Enter a balanced complete ionic equation for

HCl(aq)+LiOH(aq)→H2O(l)+LiCl(aq)

CaS(aq)+BaCl2(aq)→BaS(s)+CaCl2(aq)

NaOH(aq)+HNO3(aq)→H2O(l)+NaNO3(aq)

Na3PO4(aq)+ZnCl2(aq)→Zn3(PO4)2(s)+NaCl(aq)

Respuesta :

A balanced ionic equation shows the specie that is present in the reaction.

What is a balanced ionic equation?

A balanced ionic equation shows the specie that is present in the reaction. The ions that undergo change appear in the final ionic equation. Let us now write the ionic equation for each reaction.

In the case of reaction 1;

H^+(aq) + Cl^-(aq) + Li^+(aq) + OH^-(aq) ---->H2O(l) + Li^+(aq) + Cl^-(aq)

Reaction 2;

Ca^2+(aq) + 2Cl^-(aq) + Ba^2+(aq) + S^2-(aq) -----> BaS(s) + Ca^2+(aq) + 2Cl^-(aq)v

Reaction 3;

Na^+(aq) + NO3^-(aq) + H^+(aq) + OH^-(aq) ---->H2O(l) + Na^+(aq) + NO3^-(aq)

Reaction 4;

6Na^+(aq)  + 6Cl^-(aq) + 3Zn^2+ + 2PO4^3-(aq) -----> Zn3(PO4)2(s) + 6Na^+(aq)  + 6Cl^-(aq)

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