Based on the calculations, the differential height (h) of the mercury column is equal to 0.582 m or 58.2 cm.
How to calculate the differential height?
First of all, we would highlight the necessary parameters to be used in determining the differential height (h) of the mercury column as follows:
- Density of water = 1000 kg/m³.
- Specific gravity of oil is 0.72.
- Specific gravity of mercury is 13.6.
Next, we would determine the differential height (h) of the mercury by using this expression:
[tex]\frac{P{_1, gage}}{\rho_w} = SG_{oil}h_{oil} + SG_{Hg}h_{Hg} - h_w[/tex]
Substituting the given parameters into the formula, we have;
[tex]\frac{80 \times 10^3}{9.81 \times 1000} = (0.72 \times 0.75)+ 13.6h_{Hg} - 0.3[/tex]
Differential height of mercury (Hg) = 0.582 m or 58.2 cm.
Read more on density here: brainly.com/question/3173452
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