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A passenger on the ferris wheel normally weighs 585 N. The ferris wheel has a 13 m radius and is equipped with a powerful motor. The operator revs it up so that the customers at the top of the wheel feel zero g’s (they momentarily lift slightly off their seats). The acceleration of gravity is 9.8 m/s 2 . At what angular velocity will this occur? Answer in units of 1/s.

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okpalawalter8

A passenger on the Ferris wheel normally weighs 585 N,  the angular velocity  this will occur at is mathematically given as

w=0.867 1/s.

What angular velocity will this occur?

Generally, the equation for Linear velocity is mathematically given as

[tex]V=\sqrt{Rg}[/tex]

Therefore

[tex]V=\sqrt{13 *9.8}[/tex]

V= 11.28m/s

In conclusion,  angular velocity  is

v/r=w

Hence

w=11.28m/s/ 13 m

w=0.867 1/s.

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