The solution to x^2 + 8x = 38 is x = -4 + √54 and x = -4 - √54
How to solve the equation?
The equation is given as:
x^2 + 8x = 38
Take the coefficient of x
k = 8
Divide by 2
k/2 = 4
Square both sides
(k/2) = 16
Add 16 to both sides of x^2 + 8x = 38
x^2 + 8x + 16 = 54
Express as perfect squares
(x + 4)^2 = 54
Take the square root of both sides
x + 4 = ±√54
Subtract 4 from both sides
x = -4 ±√54
Split
x = -4 + √54 and x = -4 - √54
Hence, the solution to x^2 + 8x = 38 is x = -4 + √54 and x = -4 - √54
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