is it mathematically correct to say that:
[tex]\frac{\sqrt{13*2} }{\sqrt{13} }[/tex]


so just cancel out the 13's with each other and the answer is going to be [tex]\sqrt{2}[/tex]?

Respuesta :

Answer: Yes

Step-by-step explanation:

    Since the numerator is multiplying square root 13 by square root 2, we can break them apart.

[tex]\displaystyle \frac{\sqrt{13*2}}{\sqrt{13}} =\frac{\sqrt{13}*\sqrt{2} }{\sqrt{13}}[/tex]

   You are correct, [tex]\sqrt{13}[/tex] over  [tex]\sqrt{13}[/tex] is equal to one, so we can "cancel them out" of our expression.

[tex]\displaystyle \frac{\sqrt{13} }{\sqrt{13}} = 1[/tex]

   This leaves us with: [tex]\sqrt{2}[/tex]

We can also test this by using a calculator:

[tex]\frac{\sqrt{13*2}}{\sqrt{13}} \approx 1.41421356\\\sqrt{2} \approx 1.41421356\\1.41421356=1.41421356[/tex]