The functions that have roots at x = -1 and x = 4 are
j(x) = (-1-x)(2x-8) and g(x) = (x+1)(x-4)
The functions that have roots at x = -4 and x = -1 are
h(x) = (-3-3x)(3x+12) and k(x) = (x+1)(x+4)
The functions that have roots at neither are
f(x) = (x-1)(x-4) and (3-3x)(3x-12)
Quadratic equation
From the question, we are to determine the quadratic functions that have the given roots
First, we will determine the roots of the given functions
Since the roots of a quadratic function will make the factors equal to 0,
Then,
(x+1)(x+4) = 0
x + 1 = 0 OR x + 4 = 0
x = -1 OR x = -4
(3-3x)(3x-12) = 0
Then,
3 - 3x = 0 OR 3x -12 = 0
3x = 3 OR 3x = 12
x = 3/3 OR x = 3/12
x = 1 OR x = 4
(x+1)(x-4) = 0
Then,
x+1 = 0 OR x-4 = 0
x = -1 OR x = 4
(x-1)(x-4) = 0
Then,
x -1 = 0 OR x -4 = 0
x = 1 OR x = 4
- For h(x) = (-3-3x)(3x+12)
(-3-3x)(3x+12) = 0
Then,
-3 -3x = 0 OR 3x + 12 = 0
3x = -3 OR 3x = -12
x = -3/3 OR x = -12/3
x = -1 OR x = -4
(-1-x)(2x-8) = 0
Then,
-1 -x = 0 OR 2x - 8 = 0
x = -1 OR 2x = 8
x = -1 OR x = 8/2
x = -1 OR x =4
Hence,
The functions that have roots at x = -1 and x = 4 are
j(x) = (-1-x)(2x-8) and g(x) = (x+1)(x-4)
The functions that have roots at x = -4 and x = -1 are
h(x) = (-3-3x)(3x+12) and k(x) = (x+1)(x+4)
The functions that have roots at neither are
f(x) = (x-1)(x-4) and (3-3x)(3x-12)
Learn more on Quadratic equations here: https://brainly.com/question/23680118
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