PLEASE HELP!
Sulfur dioxide emissions from flue gases at 95 ° C can be removed by a commercial process involving the following reactions:
SO2 + Cl2 ---> SO2Cl2
SO2Cl2 + 2H2O ---> H2SO4 + 2HCl
H2SO4 + Ca (OH)2 ---> CaSO4 + 2H2O
Assuming 95.0% process efficiency, how many grams of calcium sulfate do we get from 100 grams of sulfur dioxide?

Respuesta :

Answer:

49.54 g

Explanation:

Let's take the masses of both calcium sulfate and sulfur dioxide formed.

Sulfur dioxide = 32 + 2(16) = 64 g

Calcium sulfate = 40 + 32 + 4(16) = 136 g

So, under ideal conditions, to produce 136 g of Calcium sulfate, we require 64 g of Sulfur dioxide.

But, it mentions the process is only 95% efficient.

Hence, taking the ratio :

[tex]\frac{64}{136} = \frac{0.95x}{100}[/tex]

[tex]0.95x = \frac{64 \times 100}{136}[/tex]

[tex]0.95x = \frac{6400}{136}[/tex]

[tex]x = \frac{800}{17} \times \frac{20}{19}[/tex]

[tex]x = \frac{16000}{323}[/tex]

x = 49.54 g (approximately)