Answer:
1 - cosΘ
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x
[tex]\frac{sin^20}{1+cos0}[/tex]
= [tex]\frac{1-cos^20}{1+cos0}[/tex] ← factor 1 - cos²Θ as a difference of squares
= [tex]\frac{(1-cos0)(1+cos0)}{1+cos0}[/tex] ← cancel 1 + cosΘ on numerator/ denominator
= 1 - cosΘ
