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Answer:
(- 4, 16 ) , ([tex]\frac{1}{2}[/tex], [tex]\frac{1}{4}[/tex] )
Step-by-step explanation:
y = x² → (1)
7x + 2y = 4 → (2)
substitute y = x² into (2)
7x + 2x² = 4 ( subtract 4 from both sides )
2x² + 7x - 4 = 0 ← in standard form
(x + 4)(2x - 1) = 0 ← in factored form
equate each factor to zero and solve for x
x + 4 = 0 ⇒ x = - 4
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex]
substitute these values into (1) for corresponding values of y
x = - 4 : y = (- 4)² = 16 ⇒ (- 4, 16 )
x = [tex]\frac{1}{2}[/tex] : y = ([tex]\frac{1}{2}[/tex] )² = [tex]\frac{1}{4}[/tex] ⇒ ( [tex]\frac{1}{2}[/tex] , [tex]\frac{1}{4}[/tex] )