mind blank pls help with #3
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Answer:
[tex]\angle C = 16.26^{\circ}[/tex]
Step-by-step explanation:
[tex]~~~~~~\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}\\\\\\\implies \cos \angle C = \dfrac{BC}{AC}\\\\\\\implies \angle C = \cos^{-1} \left(\dfrac{BC}{AC}\right)\\\\\\\implies \angle C=\cos^{-1} \left(\dfrac{24}{25}\right)\\\\\\\implies \angle C = 16.26^{\circ}[/tex]
Answer:
∠C = 16.26°
Step-by-step explanation:
Since the adjacent side and the hypotenuse are given, let's take the cosine value of ∠C.
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Given :
⇒ Adjacent side (CB) = 24 cm
⇒ Hypotenuse (CA) = 25 cm
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Taking the cos value :
⇒ cos ∠C = CB/CA
⇒ cos ∠C = 24/25
⇒ ∠C = cos⁻¹ (0.96)
⇒ ∠C = 16.26°