Answer:
(3 + 2y^2)√3y
Step-by-step explanation:
you first step in answering this question is to simplify all radicals
3√(3y) - √(27y^5) + y^2[√(75y)]
this becomes
3√(3y) - 3y^2(√3y) + 5y^2[√(3y)]
because all of them have √(3y) we can treat the √3y like a variable
so
(3 - 3y^2 + 5y^2)√(3y)
then you combine like terms
(3 + 2y^2)√3y is your answer
