The pool must have been the same depth at the start of the interval as it was at the end of the interval, option second is correct.
Finding out how much something changes over time is what the average rate of change is all about.
We have Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero.
As we know that the average rate of change can be calculated using:
= (Last quantity - starting quantity)/Time interval
The average rate of change, on the other hand, does not account for intermediate values, therefore you can't draw any conclusions about them.
In the given problem:
The average rate of change in depth = (Last quantity - starting quantity)/2
0= (Last quantity - starting quantity)
Final depth = Initial depth
Thus, the pool must have been the same depth at the start of the interval as it was at the end of the interval, option second is correct.
Learn more about the average rate of change here:
https://brainly.com/question/2530409
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