Find the surface area of isosceles trapezoidal prism given the measures shown.
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The surface area of the parallelogram based prism is 1548 units squared.
The prism has 2 parallelogram base and 4 rectangular faces.
Therefore,
surface area of the prism = 2 (area of the base) + area of the 4 rectangular faces
Therefore,
surface area of the prism = 2(12 × 17) +2(19 × 13) + 2(19 × 17)
surface area of the prism = 2(204) + 2(247) + 2(323)
surface area of the prism = 408 + 494 + 646
surface area of the prism = 1548 units²
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