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Bear weight loss during hibernation is extreme. Male black bears will typically drop between 17 to 29 percent of their body weight. Let x represent the percent of body weight loss for a male black bear. Suppose that clic follows a uniform distribution. Find the probability that the male will lose between 19.41 and 23.74 percent of their body weight.

Respuesta :

Using the uniform distribution, it is found that there is a 0.3608 = 36.08% probability that the male will lose between 19.41 and 23.74 percent of their body weight.

What is the uniform probability distribution?

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

In this problem, male black bears will typically drop between 17 to 29 percent of their body weight, hence the bounds are a = 17 and b = 29.

The probability that the male will lose between 19.41 and 23.74 percent of their body weight is given by:

[tex]P(19.41 \leq X \leq 23.74) = \frac{23.74 - 19.41}{29 - 17} = 0.3608[/tex]

More can be learned about the uniform distribution at https://brainly.com/question/13889040

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