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A helium balloon with an internal pressure of 1.00 atm and a volume of 4.50 L at 20.0˚C is released. What volume will the balloon occupy at an altitude where the pressure is 0.600 atm and the temperature is –20.0˚C?

GAS LAW:

Given:

Unknown:

Formula:

Solution:

FInal Answer: V2 =

Respuesta :

AnjulaReddy
hey there!

The Gas law is COMBINED GAS LAW

GIVEN :

P1=1.00 atmp
V1=3.50 lit
T1 = 20.0°C = 293K
P2=0.600 atmp
T2=-20.0°C=253K

Now,

Formula =>

P1V1/T1 =P2V2/T2

=> V2 = (P1/P2)(T2/T1)(V1)

=> V2 = (1.00/0.60)(253/293)(3.50)

=>V2 = 5.01403 L

=> V2 = 5L (approx).

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