contestada

Which of the following are solutions to the equation cos^2 2x-1/4=0? Check all that apply.
A. 11pi/3
B. 12pi/6
C. 5pi/6
D. Pi/6

Respuesta :

jasonwhite3369

Answer:

D

Step-by-step explanation:

Cos^2 2x=1/4

Cos 2x =+-1/2

2x=z

Cos z=+-1/2

z1=pi/3

z2=11pi/3

z1 and z2 are possible.

x1=pi/6

x2=11pi/6

Otras preguntas