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The volume of a gas filled balloon is 22L at 313K and 1.5 atm. What would the volume be at 273K and 1 atm?

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payounge

Answer:

28L

Explanation:

V1 = 22L                             V2 = ?

T1 = 313K                            T2 = 273K

P1 = 1.5atm                          P2 = 1.0atm

Using the combined gas law equations;

[tex]\frac{P1V1}{T1}= \frac{P2V2}{T2}[/tex]

∴[tex]V2 = \frac{P1V1}{T1} * \frac{T2}{P2}[/tex]

         = [tex]\frac{1.5*22}{313} * (\frac{273}{1})[/tex]

   V2 = 28L

pstnonsonjoku

From the calculations and the statement of the general gas equation, the volume of the gas becomes 28.8 L

What are gas laws?

The gas laws are used to show the relationship between the variables in problems that has to do with gases.

In this case, we have to apply the general gas law as follows;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 =   * 22L *  1.5 atm * 273K/313K * 1 atm

V2 = 28.8 L

Learn more about gas laws:https://brainly.com/question/12667831

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