Respuesta :
The answer is 0.46 ml of the original H₂S0₄ and dilute to a final volume of 100 ml.
What is Normality ?
Normality is a measure of concentration equal to the gram equivalent weight per liter of solution.
Normality = Number of gram equivalents × [volume of solution in litres]⁻¹
Preparing 100. ml of 0.1 N H₂S0₄
Eq. wt. of H₂S0₄ = 98/2=49
density of H₂S0₄= 1.08
Purity =98%
1 N H₂S0₄ = 49 gH₂S0₄ / liter
1 gm equiv wt /L x 1 gm equiv. wt / 2 = 98 / 2 = 49 g)
0.1 N H2SO4 = 4.9 g / L
To make 100 ml (0.100 L) we would need 4.9 [tex]\rm \frac{g}{L}[/tex] x 0.1 L
= 0.49 g H₂S0₄/100ml
Original density = 1.08 g / ml
with a purity of 98%,
this converts to 1.08 g x 0.98 = 1.058 g /ml
0.49 g H₂S0₄ x 1 ml / 1.058 g = 0.46 ml of original H₂S0₄needed
Therefore to make the desired solution
Take 0.46 ml of the original H₂S0₄ and dilute to a final volume of 100 ml.
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