Answer:
1. smaller value of t = 5
larger value of t = 9
2. (7, 4)
Step-by-step explanation:
Given function: [tex]h(t)=-(t-7)^2+4[/tex]
To find the zeros, set the function to zero and solve for t:
[tex]\begin{aligned}h(t) & =0\\\implies -(t-7)^2+4 & =0\\-(t-7)^2 & =-4\\(t-7)^2 & =4\\t-7 & =\sqrt{4}\\t-7 & =\pm 2\\t & =7\pm 2\\t & = 5,9\end{aligned}[/tex]
Vertex form: [tex]y=a(x-h)^2+k[/tex] where (h, k) is the vertex
Therefore, the vertex of the given function is (7, 4)
