Respuesta :

Answer:

D

Step-by-step explanation:

Given :

  • [tex]\sqrt[5]{224x^{11}y^{8} }[/tex]

Solving :

  • The maximum number of x we can bring out is 11/5 = 2
  • The maximum number of y we can bring out is 8/5 = 1
  • The maximum number of 2 we can bring out : 224 = 2⁵ x 7 = 5

Hence :

  • [tex]\sqrt[5]{224x^{11}y^{8} }[/tex]
  • 2x²y [tex]\sqrt[5]{7xy^{3} }[/tex]
  • D
Hrishii

Answer:

D. [tex]\huge 2x^2y\sqrt[5]{7xy^3}[/tex]

Step-by-step explanation:

  • [tex]\huge\sqrt[5]{224.x^{11}.y^8}[/tex] (Given)

  • [tex]=\huge\sqrt[5]{2^5.7.x^{10+1}.y^{5+3}}[/tex]

  • [tex]=\huge\sqrt[5]{2^5.7.x^{10}.x.y^{5}.y^3}[/tex]

  • [tex]=\huge 2.x^2.y\sqrt[5]{7.x.y^3}[/tex]

  • [tex]=\huge 2x^2y\sqrt[5]{7xy^3}[/tex]

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