Answer:
1) The smaller t is -6
The larger t is 7
2) The vertex of the parabola is (1/2, -42.25)
Step-by-step explanation:
Hey there!
To find the zeros of a function, you need to find two values that add up to "b" and multiply together to get "ac"
The b and ac come from the standard form of a parabola which this statement is given to us right now
t^2-t-42
1 is the "a" value, -1 is the "b" value, and -42 is the "c" value
What are two numbers that multiply together and get -42 and those same two numbers add up to -1
Those two numbers are -7 and 6
When you multiply those numbers together, you get -24
And when you add them together, you get -1
Now you can split the -t in the equation
The new equation after splitting the original equation will look like this
t^2-7t+6t-42
Now we group the equation into two parts
(t^2-7t) + (6t-42)
Since t is the common variable in the first set of parentheses, we can take it out
t(t-7)+(6t-42)
Now in the second pair of parentheses, 6 is the constant term
You can also take that out
t(t-7)+6(t-7)
Now we have our zero pairs
We take one of the parentheses and the terms that are outside of the parentheses
Now we have
(t+6)(t-7)=0
Now we can find our two zeros
The smaller t is -6
The larger t is 7
Now we have to find the vertex
The formula to solving the x-coordinate of the vertex is -b/2a
The "b: value is -1 and the "a" value is 1
So, the x-coordinate of the vertex is 1/2
Now we plug that into the equation
(1/2)^2 - 1/2 - 42
1/4 - 1/2 - 42
-1/4 - 42
-169/4 --> -42.25
So, the y-coordinate of the vertex s -42.25
This means,
The vertex of the parabola is (1/2, -42.25)
