khamdagreat khamdagreat
  • 14-05-2022
  • Mathematics
contestada

h(x) = x2 + 1 k(x) = x – 2

(h + k)(2) =
(h – k)(3) =
Evaluate 3h(2) + 2k(3) =
.

Respuesta :

versacci24
versacci24 versacci24
  • 14-05-2022
(h+k) = x^2 + x - 1

so (h+k)(2) assuming it is a function
= 4 + 2 - 1
= 5

(h+k)(3) = 9 + 3 - 1
= 11

3h(2) = 3*(4+1)
= 15

2k(3) = 2*(1) = 2

so 3h(2) + 2k(3) = 15 + 2


= 17
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