BliiZzzz
contestada

A tank (not rigid) contains 2.3L of
helium gas at 25°C. What will be the
volume of the tank after heating it
and its content to 40°C temperature
at constant pressure?

Given:
Unknown:
Formula:
Solution:
Final Answer:​

A tank not rigid contains 23L of helium gas at 25C What will be the volume of the tank after heating it and its content to 40C temperature at constant pressureG class=

Respuesta :

Convert

  • Temp to Kelvin
  • 25°C=298K
  • 40°C=313K

Apply Charles law

  • V1T2=V2T1
  • 2.3(313)=298V2
  • 719.9=298V2
  • V2=2.4L

Answer:

See below ~

Explanation:

Q1

Given :

  • V₁ = 2.3L
  • T₁ = 25°C = 298 K
  • T₂ = 40°C = 313 K

Unknown :

  • V₂

Formula :

  • V₁/T₁ = V₂/T₂ (Charles Law)

Solution :

  • 2.3/298 = V₂/313
  • V₂ = 313/298 x 2.3
  • V₂ = 1.05 x 2.3
  • V₂ = 2.42 L

Final Answer :

  • 2.42 L

Q2

Given :

  • P₁ = 1.01 atm
  • V₁ = 6 L
  • V₂ = 3 L

Unknown :

  • V₂

Formula :

  • P₁V₁ = P₂V₂

Solution :

  • 1.01 x 6 = P₂ x 3
  • P₂ = 1.01 x 2
  • P₂ = 2.02 atm

Final Answer :

  • 2.02 atm