contestada

A 3.24-gram sample of NaHCO3 was completely decomposed in an experiment.

2NaHCO3 → Na2CO3 + H2CO3

In this experiment, carbon dioxide and water vapors combine to form H2CO3. After decomposition, the Na2CO3 had a mass of 2.19 grams.

Determine the mass of the H2CO3 produced.
Calculate the percentage yield of H2CO3 for the reaction. Show your work or describe the calculation process in detail.

PLEASE HELP, WILL MARK BRAINLIEST!!!

Respuesta :

Mass of H2CO3 = 1.05g

Givens: NaHCO3 = 3.24
Na2CO3 = 2.19
To get the mass, just subtract the mass of one of the product to the reactant.

Mass of H2CO3 = mass of NaHCO3 - mass of Na2CO3

Mass of H2CO3 = 3.24g - 2.19g

Mass of H2CO3 = 1.05g
abbusaicharan02

Mass of H2CO3 = 1.05g

Givens: NaHCO3 = 3.24

Na2CO3 = 2.19

Mass of H2CO3 = mass of NaHCO3 - mass of Na2CO3

Mass of H2CO3 = 3.24g - 2.19g

Mass of H2CO3 = 1.05g

How do you find the mass number?

The number of protons and the number of neutrons combine to determine the mass number of an element. Mass number = proton + neutron. If you want to calculate the number of neutrons an atom has, you can simply subtract the number of protons or atomic numbers from the mass number.

Divide the mass of a substance in grams by the molecular weight. This will give you the number of moles of the substance in a particular mass. For 12 g of water, (25 g) / (18.015 g / mol) = 0.666 mol.

Learn more about decomposition reaction here: https://brainly.com/question/27300160

#SPJ2

Otras preguntas