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73-74 express the limit as a definite integral.
73. [tex]\lim _{n \rightarrow \infty} \sum_{i=1}^{n} \frac{i^{4}}{n^{5}}[/tex] [hint: consider [tex]$f\mleft(x\mright)=x^4$.\rbrack[/tex]

Respuesta :

LammettHash

Pull out a factor of 1/n from the summand and the result follows.

[tex]\displaystyle \lim_{n\to\infty} \sum_{i=1}^n \frac{i^4}{n^5} = \lim_{n\to\infty} \frac1n \sum_{i=1}^n \left(\frac in\right)^4 = \boxed{\int_0^1 x^4 \, dx}[/tex]

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