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if 500 g of iron absorbs 22000 cal of heat, what will be the change in temperature? (specific heat of iron = 0.11 cal/gC)

Respuesta :

Answer:

400°C

Explanation:

22,000 cal / (0.11 cal/g°C x 500 g) = 400°C

Answer:

400 C degree change

Explanation:

22 000 cal = 500 g * (C) * .11 cal / g-C

C = 22 000 / (500*.11)   = 400 C  degree change