A traveler pulls a suitcase, as shown in the figure.

The force acting on the handle is 30 N at an angle of θ = 40°. How much work is done if the traveler moves 120 meters? Round to the nearest whole number.

2,314 Nm
2,758 Nm
3,085 Nm
4,156 Nm

&

A cart weighing 180 pounds rests on an incline at an angle of 35°. What is the required force to keep the cart at rest? Round to the thousandths place.

77.073 pounds
103.244 pounds
147.447 pounds
162.665 pounds

Respuesta :

Answer:

2758 Nm

Step-by-step explanation

Work done usually depends on two things force applied and distance travelled due to applied force. In this current scenario, the force is being applied at an angle so we will have to find a component of force in the direction of the movement.

We usually find component using cos θ.

Here θ is 40°

Now, the modified equation becomes,

Work Done = Force * Distance * Component of force along the direction of distance

∴ Work = 30 N * 120 m * Cos 40°

⇒Work = 30 * 120 * 0.766

Work = 2757.6 Nm

Rounding to the nearest whole number.

∴ The work done by force is 2758 Nm which is option B

Ver imagen swayampendgaonkar

The amount of work done will be 2758 Nm. Then the correct option is B. And the required force to keep the cart at rest will be 147.447 pounds. Then the correct option is C.

What is work done?

The product of the force and displacement.

WD = F × d × cos θ

A traveler pulls a suitcase, as shown in the figure.

The force acting on the handle is 30 N at an angle of θ = 40°.

Then the amount of work done if the traveler moves 120 meters will be

WD = 30 × 120 × cos 40°

WD = 30 × 120 × 0.766

WD = 2758 Nm

Then the correct option is B.

A cart weighing 180 pounds rests on an incline at an angle of 35°.

The required force to keep the cart at rest will be

Fₓ = F × cos θ

Fₓ = 180 × cos 35°

Fₓ = 147.447 pounds

Then the correct option is C.

More about the work done link is given below.

https://brainly.com/question/13662169

#SPJ5