Respuesta :
(a)The domain of the function is, [tex]\rm x \geq -c^2 \ x\neq0[/tex]
(b)The given function is discontinuous at x=0.
What is the domain and range of a function?
Domain is the set of values for which the given function is defined. Range is the set of all values which the given function can output.
The standard function is;
[tex]\rm f(x)= \frac{\sqrt{x+c^2-c} }{x} , c > 0[/tex]
The domain of the given function is found as;
[tex]\rm x+c^2 \geq 0 \ x\neq 0 \\\\ x\geq-c^2 \ x\neq 0[/tex]
The domain of the function is,
[tex]\rm x \geq -c^2 \ x\neq0[/tex]
To find the function is continuous or not, we have to find the continuity;
[tex]\rm f(x) = \frac{\sqrt{ x+c^2-c}}{x} ,c > 0[/tex]
At x= 0 the function is undefined. So that the function is discontinuous at x=0.
Hence, The domain of the function is, [tex]\rm x \geq -c^2 \ x\neq0[/tex] and the function is discontinuous at x=0.
To learn more about domain, refer to the link:
https://brainly.com/question/20073127
#SPJ1
