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A 0.50 kg lead ball at 45 c is dropped into a calorimeter with water at 20 the final temperature of the ball-water system is 25c, what is the mass of the water? consider specific heat capacity of led = 128 / k * g degrees * c and specific heat capacity of water=4186 //kg^ c

Respuesta :

Answer:

.0612 kg

Explanation:

I think your spec heat for lead should be   128 j /kg-K

Final lead temp is the same as the water 25 C   Note that 1 K = 1 C degree

 so lead goes from 45 to 25 C     (or difference of 20 K)

Heat given up by the lead =

.5 kg * (20 K)  * 128 j/ kg -C   = 1 280  j

this heat is GAINED by the water going from 20 to 25  C

x kg * (5 C ) (4186  j/kg-C )  = 1 280  j  

x = .0612 kg

 

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