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A tourist, who weighs 805 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops one-fourth of the way along the bridge. Assume that the board of the bridge has negligible weight. What is the magnitude of the vertical force that a concrete support exerts on the bridge at the far end?

Respuesta :

The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.

What is force?

The force is an action of push or pull which makes a body to move or stop.

Given is the weight of tourist W = 805 N and L is the length of the bridge.

Let the reaction force at both the ends of the bridge is R1 and R2.

Taking the moments about point A,

R1 x 0 - W x L/4 +R2 x L =0

R2 = W/4

R2 = 805 /4

R2 = 201.25 N

Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.

Learn more about force.

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