Since the customers can choose among 5 drinks, 4 main dishes, and 5 sides. there 100 different combo meals are possible.
Since order is not important we use combination to solve the problem
What is combination?
This is the number of ways in which x objects can be selected out of n objects. It is given mathematically as ⁿCₓ = n!/x!(n - x)!
The number of different combo meals
Now, given that the customer can choose among 5 drinks, 4 main dishes, and 5 sides.
There are ⁵C₁ ways of choosing the drinks.
So, ⁵C₁ = 5!/1!(5 - 1)!
= 5!/1!/4!
= 5
There are ⁴C₁ ways of choosing the main dishes.
So, ⁴C₁ = 4!/1!(4 - 1)!
= 4!/1!/3!
= 4
There are ⁵C₁ ways of choosing the sides.
So, ⁵C₁ = 5!/1!(5 - 1)!
= 5!/1!/4!
= 5
So, total number of ways of choosing the combo meals is
⁵C₁ × ⁴C₁ × ⁵C₁ = 5 × 4 × 5
= 100 ways.
So, there 100 different combo meals are possible.
Learn more about combination here:
https://brainly.com/question/26852614
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