Answer:
a = 25 m²
b = 5 m
c = 7.94 m
d = 35.73 m²
Code: H I A B
Step-by-step explanation:
Formulae
Pythagoras’ Theorem: [tex]a^2+b^2=c^2[/tex]
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
Area of a square = x² (where x is the side length)
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Assuming that all the quadrilaterals are squares.
Side length of blue square with area 16 m² = √16 = 4 m
Side length of yellow square with area 9 m² = √9 = 3 m
Use Pythagoras' Theorem to find the length of b:
[tex]\implies 4^2+3^2=b^2[/tex]
[tex]\implies b^2=25[/tex]
[tex]\implies b=\sqrt{25}[/tex]
[tex]\implies b=5\: \sf m[/tex]
Now we have found length b, we can find area a:
[tex]\textsf{Area a}=b^2=5^2=25\: \sf m^2[/tex]
Side length of purple square with area 144 m² = √144 = 12 m
Side length of green square with area 81 m² = √81 = 9 m
Use Pythagoras' Theorem to find the length of c:
[tex]\implies 9^2+c^2=12^2[/tex]
[tex]\implies c^2=63[/tex]
[tex]\implies c=\sqrt{63}[/tex]
[tex]\implies c=3\sqrt{7}[/tex]
[tex]\implies c=7.94\: \textsf{(nearest hundredth)}[/tex]
Now we have found length d, we can find area d:
[tex]\textsf{Area d}=\dfrac{1}{2}(9)(7.94)=35.73\: \sf m^2[/tex]
Code: H I A B
