The slant height of the right circular cone will be [tex]l=2\sqrt5}[/tex]
The formula for the slant height of the cone is given as:
[tex]l^2=r^2+h^2[/tex]
Here we have
r=2 units
h=4 units
By putting the values we will get
[tex]l=\sqrt{4^2+2^2[/tex]
[tex]l=\sqrt{16+4[/tex]
[tex]l=\sqrt{20}[/tex]
[tex]l=2\sqrt{5}[/tex]
Hence the slant height of the right circular cone will be [tex]l=2\sqrt5}[/tex]
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