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Given a sorted list of integers, output the middle integer. a negative number indicates the end of the input (the negative number is not a part of the sorted list). assume the number of integers is always odd.
ex: if the input is: 2 3 4 8 11 -1
the output is:
middle item: 4
the maximum number of inputs for any test case should not exceed 9. if exceeded, output "too many numbers". hint: first read the data into a vector. then, based on the number of items, find the middle item. 276452.1593070
(must include vector library to use vectors)

Respuesta :

inputs=[]

num_inputs=int(input())

if(num_inputs>9):

   print("Too many inputs")

else:

   print(num_inputs)

   for i in range(num_inputs):

       inputs.append(input())

   print(inputs)

   middle_position=int(num_inputs/2)

   print(inputs[middle_position])

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