Respuesta :
Answer:
radius 4
center (3,6)
Step-by-step explanation:
(x - h)^2 + (y - k)^2 = r^2
coordinates of the center (h, k) and the radius is (r)
x² + y²- 6x - 12y +29=0
x² - 6x + y²- 12y +29=0
(x² - 6x) + (y²- 12y) +29=0
complete the square
(x² - 6x) + 9 + (y²- 12y) +36 +29= + 9 +36
(x² - 6x + 9) + (y²- 12y + 36) = + 9 +36 -29
(x-3)^2 + (y-6)^2 = 16
(x - h)^2 + (y - k)^2 = r^2
coordinates of the center (h, k) and the radius is (r)
center (3,6)
radius 4
cuemathcom
varsitytutors
Answer: Center: (3,2) Radius: 5
Step-by-step explanation:#x^2 - 6x +y^2 - 4y = 12
Then take 1/2 of the 'b' term for both quadratic expressions, square those values and add them to both sides.
#x^2 -6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y -2)^2 = 25
Circle centered at (3,2) with radius = 5