The limit of x times cosine of the quantity 5 times x all over sine of the quantity 5 times x as x approaches 0 is determined as ¹/₅.
The limit of the function is determined as follows;
[tex]\lim_{x \to 0} \ \frac{sinx}{x} = 1\\\\ \lim_{x \to 0} \ \frac{x(cos5x)}{sin5x}[/tex]
The derivative of the function;
[tex]\frac{xcos(5x)}{sin5x} = \frac{-5x(sin(5x)) + cos(5x)}{5cos(5x)}\\\\= \frac{-5x(sin(5x))}{5cos(5x)} + \frac{cos(5x)}{5cos(5x)} \\\\ \lim_{x \to 0} \\\\= 0 + \frac{1}{5} = \frac{1}{5}[/tex]
Thus, the limit of x times cosine of the quantity 5 times x all over sine of the quantity 5 times x as x approaches 0 is determined as ¹/₅.
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