contestada

A password is 4 characters long and must consist of 3 letters and one number. if letters cannot be repeated and the password must end with a number, how many possibilities are there? a. 175,760 b. 158,184 c. 156,000 d. 140,400 please select the best answer from the choices provided a b c d

Respuesta :

facundo3141592

We will see that there are 156,000 different combinations, so the correct option is C.

How many possibilities are there?

First, we need to find the selections, here we have:

  • First letter.
  • Second letter.
  • Third letter.
  • Number.

Now we need to find the number of options for each of these selections.

  • First letter. (26 options)
  • Second letter. (25 options, because we can't repeat letters)
  • Third letter. (24 options)
  • Number. (10 options).

We assumed that the number can be any integer from 0 to 9.

The total number of possibilities is equal to the product between the numbers of options, we will have:

P = 26*25*24*10 = 156,000

So, the correct option is C.

IF you want to learn more about combinations.

https://brainly.com/question/11732255

#SPJ4