A chemist reacted 11.50 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.

Na + Cl2 → NaCl

If the percentage yield of the reaction is 85%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors.

Respuesta :

Actual yield is the definite mass of the product obtained from the reaction. The actual yield of the reaction is 24.83 gms.

What is the percentage yield?

Percentage yield is the proportion of the actual to the theoretical yield. The formula is given as,

% yield = Actual yield ÷ Theoretical yield × 100

The balanced chemical reaction is given as:

2 Na + Cl₂ → 2NaCl

From the reaction:

2 × 23 Na = 2 × 58.44 gm of NaCl

If, 1 gm of Na will produce = (2 × 58.44) ÷ (2 × 23)

Then, 11.50 gms sodium will produce, (2 × 58.44) ÷ (2× 23) × 11.50

= 29.22 g

So, the actual yield is calculated as:

= % yield × Theoretical yield ÷ 100

= 85 × 29.22 ÷ 100

= 24.83 g

Therefore, the actual yield of the reaction is 24.83 gms.

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