Does anybody know how to solve this?
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The area of the rectangle in the form of a polynomial is 40(x² + 6x + 5). If the width is 160 ft, then the area of the rectangle is 57,600 square ft.
It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a rectangle, opposite sides are parallel and equal and each angle is 90 degrees. And its diagonals are also equal and intersect at the mid-point.
If the length and width of the rectangle are (10x + 10) and (4x + 20). Then the area of the rectangle will be
Area = (10x + 10)(4x + 20)
Area = 40x² + 200x + 40x + 200
Area = 40x² + 240x + 200
Area = 40(x² + 6x + 5)
If the width is 160 feet then the value of x will be
4x + 20 = 160
4x = 140
x = 35
Then the area of the rectangle will be
Area = 40(35² + 6 × 35 + 5)
Area = 40(1225 + 210 + 5)
Area = 40 (1440)
Area = 57,600 square ft
More about the rectangle link is given below.
https://brainly.com/question/10046743
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