You collect a random sample of size n from a population and calculate a 95% confidence
with an increased margin of error?
O Use a 98% confidence level.
O Use a 90% confidence level.
O increase the sample size.
O Use the same confidence level, but compute the interval n times. Approximately 5% 0
© Nothing can guarantee that you will obtain a larger margin of error. You can only say



In a recent telephone survey, 5,000 randomly selected teenagers were asked to cite their primary social network site. Six of 10 teenagers said they use Mybook as
their primary social network site. A 95% confidence interval to estimate the true proportion of teenagers who use Mybook as their primary social network site is found to
be (0.2964, 0.9036). Which of the following is a correct interpretation of the confidence level?
O Ninety-five percent of all samples of this size would yield a confidence interval of (0.2964, 0.9036).
O There is a 95% chance that the true proportion of teenagers who use Mybook as their primary social network site is in the interval (0.2964, 0.9036).
O Ninety-five percent of the time, the procedure used to generate this interval will capture the true proportion of teenagers who use Mybook as their primary
social network site
O Ninety-five percent of all the samples of size 5,000 lie in the confidence interval (0.2964, 0.9036).
O There is a 95% chance that randomly selected teenagers will be part of the 60% who use Mybook as their primary social network site.



(05.04 MC)
Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple random sample of 50 of the 200 seniors on
campus. He finds that 32 like to watch football. Is the random condition for finding confidence intervals met? Explain.
O Yes, the random condition for finding confidence intervals is met because np = 32 and n(1 - P) = 18, both of which are greater than 10
O Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.
O No, the random condition for finding confidence intervals is not met because np = 32 and n(1 - p) = 18, both of which are less than 100
O No, the random condition for finding confidence intervals is not met because the sample is not at least 50% of the population
O Yes, the random condition for finding confidence intervals is met because the sample is a simple random sample.




Cilantro tastes like soap to some people. This soap taste is inherited through the olfactory receptor gene OR6A2. About 14% of the population has this gene. You wa
to estimate the proportion of Americans who have this gene. How large a sample must you test, with a 3% margin of error and 95% confidence, to estimate the
proportion of people who carry the OR6A2 gene?
O 514 people
O 134 people
O 17.689 people
O 35 people
01.028 people



The faculty members at McAdenville High School want to determine whether there are enough students to have a Winter Formal. Sixty-three of the 150 students
surveyed said they would attend the Winter Formal. Construct and interpret a 99% confidence interval for p.
O The 99% confidence interval is (0.3162, 0.5238). We are 99% confident the true proportion of students attending the Winter Formal is between 31 62% and
52.38%.
© The 99% confidence interval is (0.3162, 0.5238). There is a 99% chance that a randomly selected student who will attend the Winter Formal lies between
31.62% and 52.38%
O The 99% confidence interval is (0.3162, 0.5238). Ninety-nine percent of all samples of this size will yield a confidence interval of (0.3162, 0.5238).
O The 99% confidence interval is (0.4762, 0.6838). We are 99% confident that the true proportion of students attending the Winter Formal is between 47 62%
and 68.38%
O The 99% confidence interval is (0. 4762, 0.6838). Ninety-nine percent of all samples of this size will yield a confidence interval of (0.4762, 0.6838)

PLEASE HELP ASAP, please don’t waste my time if you don’t know what your talking about THANK YOU GUYSSS