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What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c when 2,520 j of heat is applied? use q equals m c subscript p delta t.. 0.00420 j/(gi°c) 0.00661 j/(gi°c) 238 j/(gi°c) 252 j/(gi°c)

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samueladesida43

The specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of heat is applied is 4.2 J/g°C.

How to calculate specific heat?

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

2520 = 10 × c × (70 - 10)

2520 = 600c

c = 4.2 J/g°C

Therefore, the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of heat is applied is 4.2 J/g°C.

Learn more about specific heat capacity at: https://brainly.com/question/1747943

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