please answer this question
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As it is given :
Present age of mom : Present age of son = 6 : 1
Therefore let :
Ages after 10 year :
The ages after 10 years are given in rational of 8 : 3.
Which means :
Mom's age after 10 years : Son's age after 10 years = 8 :3.
Now :
[tex] \scriptsize \purple{ \boxed{ \scriptsize \dfrac{ \text{Mom's age after 10 years}}{ \text{son's age after 10 years}}= \dfrac{8}{3} }} \star[/tex]
[tex] \\ \\ [/tex]
So :
[tex] \small\sf \dashrightarrow \dfrac{6x + 10}{x + 10} = \sf \dfrac{8}{3} [/tex]
[tex] \\ \\ [/tex]
[tex] \small\sf \dashrightarrow \dfrac{3(6x + 10)}{x + 10} = \sf \dfrac{8}{1} [/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow \dfrac{18x +30}{x + 10} = \sf \dfrac{8}{1} [/tex]
[tex] \\ \\[/tex]
[tex] \small\sf \dashrightarrow \dfrac{18x +30}{1} = \sf \dfrac{8(x + 10)}{1} [/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow 18x +30= \sf 8(x + 10)[/tex]
[tex] \\ \\ [/tex]
[tex] \small\sf \dashrightarrow 18x +30= \sf 8x + 80[/tex]
[tex] \\ \\ [/tex]
[tex] \small\sf \dashrightarrow 18x - 8x +30= \sf 80[/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow 10x +30= \sf 80[/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow 10x = \sf 80 - 30[/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow 10x = \sf 50[/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow \dfrac{10x}{10} = \sf \dfrac{50}{10} [/tex]
[tex] \\ \\ [/tex]
[tex]\small \sf \dashrightarrow \dfrac{1\cancel0x}{1\cancel0} = \sf \dfrac{5\cancel0}{1\cancel0} [/tex]
[tex] \\ \\ [/tex]
[tex] \small\bf \dashrightarrow x = \pink 5[/tex]
[tex] \\ [/tex]
We know :
[tex] \footnotesize \hookrightarrow \sf Son's \: age = x[/tex]
[tex] \footnotesize \hookrightarrow \sf Son's \: age = \red{5 \: years}[/tex]
[tex] \\ \\ [/tex]
[tex] \footnotesize \hookrightarrow \sf Mother's \: age = 6x[/tex]
[tex] \footnotesize\hookrightarrow \sf Mother's \: age = 6 \times 5[/tex]
[tex] \footnotesize \hookrightarrow \sf Mother's \: age = \bf \red{30 \: years}[/tex]
And all we are done ! ㋛