Respuesta :
The larger of the two roots of the equation [tex]y = -2.2x^2 + 63.5x - 17[/tex]would be 28.59.
How to find the roots of a quadratic equation?
Suppose that the given quadratic equation is
[tex]ax^2 + bx + c = 0[/tex]
Then its roots are given as:
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
The given quadratic equation is
[tex]y = -2.2x^2 + 63.5x - 17[/tex]
now, the roots of the equation are
[tex]x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}[/tex]
The two roots are 0.27 and 28.59.
Thus, the larger of the two roots of the equation [tex]y = -2.2x^2 + 63.5x - 17[/tex]would be 28.59.
Learn more about finding the solutions of a quadratic equation here:
https://brainly.com/question/3358603
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